#challenge
💻 Compounding Letters | #easy
Create a function that takes a string and returns a new string with each new character accumulating by +1. Separate each set with a dash.
Capitalize the first letter of each set.
Examples:
#interview
💻 Compounding Letters | #easy
Create a function that takes a string and returns a new string with each new character accumulating by +1. Separate each set with a dash.
Capitalize the first letter of each set.
Examples:
Accum("abcd") ➞ "A-Bb-Ccc-Dddd"
Accum("RqaEzty") ➞ "R-Qq-Aaa-Eeee-Zzzzz-Tttttt-Yyyyyyy"
Accum("cwAt") ➞ "C-Ww-Aaa-Tttt"
🏆 Leave your solutions in the comments. The solution will be posted below in a couple of hours 👇#interview
#challenge
💻 Letter Distance | #easy
Given two words, the letter distance is calculated by taking the absolute value of the difference in character codes and summing up the difference.
If one word is longer than another, add the difference in lengths towards the score.
To illustrate:
#interview
💻 Letter Distance | #easy
Given two words, the letter distance is calculated by taking the absolute value of the difference in character codes and summing up the difference.
If one word is longer than another, add the difference in lengths towards the score.
To illustrate:
"fly") = dist("h", "f") + dist("o", "l") + dist("u", "y") + dist(house.Length, fly.Length)
= |104 - 102| + |111 - 108| + |117 - 121| + |5 - 3|
= 2 + 3 + 4 + 2
= 11
Examples:LetterDistance("sharp", "sharq") ➞ 1
LetterDistance("abcde", "Abcde") ➞ 32
LetterDistance("abcde", "bcdef") ➞ 5
🏆 Leave your solutions in the comments. The solution will be posted below in a couple of hours 👇#interview
#challenge
💻 Pentagonal Number | #easy
Write a function that takes a positive integer num and calculates how many dots exist in a pentagonal shape around the center dot on the Nth iteration.
In the image below you can see the first iteration is only a single dot. On the second, there are 6 dots. On the third, there are 16 dots, and on the fourth there are 31 dots.
Return the number of dots that exist in the whole pentagon on the Nth iteration.
Examples:
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💻 Pentagonal Number | #easy
Write a function that takes a positive integer num and calculates how many dots exist in a pentagonal shape around the center dot on the Nth iteration.
In the image below you can see the first iteration is only a single dot. On the second, there are 6 dots. On the third, there are 16 dots, and on the fourth there are 31 dots.
Return the number of dots that exist in the whole pentagon on the Nth iteration.
Examples:
pentagonal(1) ➞ 1🏆 Leave your solutions in the comments. The solution will be posted below in a couple of hours 👇
pentagonal(2) ➞ 6
pentagonal(3) ➞ 16
pentagonal(8) ➞ 141
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#challenge
💻 Oddish vs. Evenish | #easy
Create a function that determines whether a number is Oddish or Evenish. A number is Oddish if the sum of all of its digits is odd, and a number is Evenish if the sum of all of its digits is even. If a number is Oddish, return "Oddish". Otherwise, return "Evenish".
For example, OddishOrEvenish(121) should return "Evenish", since 1 + 2 + 1 = 4. OddishOrEvenish(41) should return "Oddish", since 4 + 1 = 5.
Examples:
#interview
💻 Oddish vs. Evenish | #easy
Create a function that determines whether a number is Oddish or Evenish. A number is Oddish if the sum of all of its digits is odd, and a number is Evenish if the sum of all of its digits is even. If a number is Oddish, return "Oddish". Otherwise, return "Evenish".
For example, OddishOrEvenish(121) should return "Evenish", since 1 + 2 + 1 = 4. OddishOrEvenish(41) should return "Oddish", since 4 + 1 = 5.
Examples:
OddishOrEvenish(43) ➞ "Oddish"🏆 Leave your solutions in the comments. The solution will be posted below in a couple of hours 👇
// 4 + 3 = 7
// 7 % 2 = 1
OddishOrEvenish(373) ➞ "Oddish"
// 3 + 7 + 3 = 13
// 13 % 2 = 1
OddishOrEvenish(4433) ➞ "Evenish"
// 4 + 4 + 3 + 3 = 14
// 14 % 2 = 0
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#challenge
💻 Check for Anagrams | #easy
Create a function that takes two strings and returns either true or false depending on whether they're anagrams or not.
Examples:
#interview
💻 Check for Anagrams | #easy
Create a function that takes two strings and returns either true or false depending on whether they're anagrams or not.
Examples:
IsAnagram("cristian", "Cristina") ➞ true
IsAnagram("Dave Barry", "Ray Adverb") ➞ true
IsAnagram("Nope", "Note") ➞ false
🏆 Leave your solutions in the comments. The solution will be posted below in a couple of hours 👇#interview